Duplicating recurring rows

so far, I've found this in the manual. however, it's still unclear how to choose every tenth value...

wave1[1,*;2] = 100 // sets every odd point of wave0

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extract originalWave,resultWave,mod(p,10)==0 will probably do what you want.

A

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Hmm, I think this will do the job, too:
To extract every tenth value make a wave which has n/10 rows (20 in your case):

make/n=20 newwave

Then use the row counter 'p' in the expression (will count through all rows of newwave, i.e. 0....19):

newwave = wave1[10*(p+1)] // extract point 10, 20, 30, 40, ...

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chozo wrote:

newwave = wave1[10*(p+1)] // extract point 10, 20, 30, 40, ...

Of course this works as well as my approach. Just be carefull with indexing on the right side of the equation. Your example doesn't extract a value from the first 10 points of wave1 and in return two values from the last 10 points of wave1. Used in a user-defined function compiled with #pragma rtGlobals=3, it would actually throw an error, because the index runs to 200.
Use newwave = wave1[10*p+j] where j is the first point that gets extracted and should be from the interval [0,9]. So choose j=0 (or omit j) if you want to extract points 0, 10, 20, 30, ..., or j=1 to extract the points 1, 11, 21, 31, ..., etc.

A

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