Formatted print with % as a printed character

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Wed, 10/24/2018 - 06:45 am 

HI--
    I'm trying to print to a notebook or in the command window something that would look like this:
"Bob​     78%     66%"
I'm guessing that the % after the first %d is causing me to get a "format string invalid" error message.
I can get around this by doing 2 printfs without the end carriage return but that seems kind of cluegy. 
Is there a more elegant, ie correct, way of doing this. What is shown below doesn't work.
string name = "Bob"
variable meetstat=78
variable campstat = 60
printf "%s  \t\t    %d% \t\t\t\t%d% \r",name, meetstat, campstat

Any advice is, as always, very much appreciated. Thanks

ssmith

Try:

string name = "Bob"
variable meetstat=78
variable campstat = 60
printf "%s  \t\t    %d%% \t\t\t\t%d%% \r",name, meetstat, campstat

 

October 24, 2018 at 06:54 am - Permalink

KurtB--

    Thats the ticket!! Thanks a lot. Can you explain the logic/reason that this works? That is to say the IGOR logic that is taking place? Thanks again.

 

ssmith

October 24, 2018 at 07:53 am - Permalink

This is a feature of Printf. Since % has special interpretation, we need a way to represent a literal % character.

This is stated in the documentation for Printf, but it could be more explicit. See the section that starts "Here is a complete list of the conversion characters supported by printf". It lists all of the "conversion characters", i.e., characters that follow a % character that starts a conversion sequence.

Among the listed conversion characters is %. This means that you have the % character that introduces the conversion sequence followed by another % character.

As I say, it could be more explicit. I have made a note to improve the documentation.

October 24, 2018 at 09:28 am - Permalink