simple color mixing
chriswo
Thu, 06/04/2015 - 12:32 am
I want to more or less automatically colorize my traces in any given plot using a small program:
The idea is just to mix the rgb values in equidistant steps, similar to the "make traces different" package, however with selfdefined colors (two at the moment).
The code appears to be ok, as far as I can tell, but i don't understand, why it won't work (i.e. it colorizes all traces black)
I tried it with and do-while loop too, wasn't succesful either, can you guys please help?
function mixcolors(c1r,c1g,c1b,c2r,c2g,c2b)
variable c1r,c1g,c1b,c2r,c2g,c2b
variable i
i=0
// count the number of traces in the graph
string names=tracenamelist("",";",1),name
variable count=itemsinlist(names)
//iterate through the traces and change their colors
for(i=0;i<count;i+=1)
ModifyGraph/Z rgb[i]=(round(abs(c1r-i*(c1r-c2r)/count)),round(abs(c1g-i*(c1g-c2g)/count)),round(abs(c1b-i*(c1b-c2b)/count)))
endfor
end
variable c1r,c1g,c1b,c2r,c2g,c2b
variable i
i=0
// count the number of traces in the graph
string names=tracenamelist("",";",1),name
variable count=itemsinlist(names)
//iterate through the traces and change their colors
for(i=0;i<count;i+=1)
ModifyGraph/Z rgb[i]=(round(abs(c1r-i*(c1r-c2r)/count)),round(abs(c1g-i*(c1g-c2g)/count)),round(abs(c1b-i*(c1b-c2b)/count)))
endfor
end
I plan to implement a hex2rgb converter once this works to get rid of the 6 input variables, but that's a different story.
rgb[i], the i value is an integer. You need to create a string and take the tracename from the list and put that there. Something like (untested):variable c1r,c1g,c1b,c2r,c2g,c2b
string tname
variable i
// count the number of traces in the graph
string names=tracenamelist("",";",1),name
variable count=itemsinlist(names)
//iterate through the traces and change their colors
for(i=0;i<count;i+=1)
tname=stringfromlist(i,names)
ModifyGraph/Z rgb($tname)=(round(abs(c1r-i*(c1r-c2r)/count)),round(abs(c1g-i*(c1g-c2g)/count)),round(abs(c1b-i*(c1b-c2b)/count)))
endfor
end
June 4, 2015 at 02:10 am - Permalink
Actually for completeness, I've worked it out in the meanwhile like this:
variable c1r,c1g,c1b,c2r,c2g,c2b
variable i
i=0
// count the number of traces in the graph
string names=tracenamelist("",";",1),name
variable count=itemsinlist(names)
do
ModifyGraph/Z rgb[i]=(round(abs(c1r-i*(c1r-c2r)/count)),round(abs(c1g-i*(c1g-c2g)/count)),round(abs(c1b-i*(c1b-c2b)/count)))
i+=1
while(i<=count)
end
June 4, 2015 at 04:01 am - Permalink
FWIW: equal distances in RGB color-space are not equal distances in terms of human color perception. For that, you need to work in Lab color space.
I am not aware of a good general solution for picking up 'count' most distinct colors for a graph (even is you assume a starting color say c1). My own preference is to use HSL color-space. For small 'count' I simply divide the hue circle in equal intervals.
A.G.
June 4, 2015 at 07:29 am - Permalink
//http://en.wikipedia.org/wiki/HSL_and_HSV
// Igor uses 240 as maximum for Hue, Sat & Lum
Variable Hue, Sat, Lum, Ch
Variable H, C, X, m
Variable R, G, B
If (NumType(Hue)!=0)
Return 0
EndIf
Hue=Mod(Hue,240)
Sat=Sat/240
Lum=Lum/240
H=Hue/40
C=(1-Abs(2*Lum-1))*Sat
X=C*(1-Abs(Mod(H,2)-1))
If (H<1)
R=C; G=X; B=0
ElseIf (H<2)
R=X; G=C; B=0
ElseIf (H<3)
R=0; G=C; B=X
ElseIf (H<4)
R=0; G=X; B=C
ElseIf (H<5)
R=X; G=0; B=C
Else
R=C; G=0; B=X
EndIf
m=Lum-C/2
Switch (Ch)
Case 0:
Return (R+m)*65535
Break
Case 1:
Return (G+m)*65535
Break
Case 2:
Return (B+m)*65535
Break
EndSwitch
End
and run it with
modifygraphas follows:RGB($ExpName)=(HSL2RGB(i*210/NumExp+50, 240, 100, 0), HSL2RGB(i*210/NumExp+50, 240, 100, 1), HSL2RGB(i*210/NumExp+50, 240, 100, 2))also have a look at the "Make Traces Different" package hidden in the "Graph/Packages" menu.
HJ
June 4, 2015 at 07:59 am - Permalink