amtravco OK, I've figured out that E(k) = (pi/2)*hyperG2F1(-1/2, 1/2, 1, k^2) and K(k) = (pi/2)*hyperG2F1(1/2, 1/2, 1, k^2). Maybe not the most efficient implementation, but it will do the job. Log in or register to post comments April 18, 2020 at 06:29 pm - Permalink
OK, I've figured out that
E(k) = (pi/2)*hyperG2F1(-1/2, 1/2, 1, k^2)
and
K(k) = (pi/2)*hyperG2F1(1/2, 1/2, 1, k^2).
Maybe not the most efficient implementation, but it will do the job.
April 18, 2020 at 06:29 pm - Permalink